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6. Electromagnetic induction — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics6. Electromagnetic induction1 Mark
MCQ
A conducting rod of length $2l$ is rotating with constant angular speed $omega$ about its perpendicular bisector. A uniform magnetic field $\overrightarrow B $ exists parallel to the axis of rotation. $The e.m.f.$ induced between two ends of the rod is
  • A
    $B$ $\omega$l2
  • B
    $\frac{1}{2}B\omega {l^2}$
  • C
    $\frac{1}{8}B\omega {l^2}$
  • ✓
    $Zero$
✓

Answer

Correct option: D.
$Zero$
d
(d) Potential difference between

$O$ and $A$ is ${V_0} - {V_A} = \frac{1}{2}B{l^2}\omega $

 $O$ and $B$ is

${V_0} - {V_B} = \frac{1}{2}B{l^2}\omega $

so ${V_A} - {V_B} = 0$

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