- ✓$\frac{3 A_0}{4}$
- B$A_0$
- C$4 A_0$
- D$12 A_0$
$\tau=\frac{\Delta L}{\Delta t}$
$\tau=\frac{4 A_0-A_0}{4}=\frac{3 A_0}{4}$
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(Surface tension of water $=0.075 N / m$, density of water $=1000 kg / m ^3$, take $g =10 m / s ^2$ )
$(1)$ The correction in the height of water column raised in the tube, due to weight of water contained in the meniscus, will be different for both cases.
$(2)$ For case I, if the capillary joint is $5 cm$ above the water surface, the height of water column raised in the tube will be more than $8.75 cm$. (Neglect the weight of the water in the meniscus)
$(3)$ For case $I$, if the joint is kept at $8 cm$ above the water surface, the height of water column in the tube will be $7.5 cm$. (Neglect the weight of the water in the meniscus)
$(4)$ For case II, if the capillary joint is $5 cm$ above the water surface, the height of water column raised in the tube will be $3.75 cm$. (Neglect the weight of the water in the meniscus)


Reason : The dipoles of a polar dielectric are randomly oriented.
