MCQ
A current carrying loop is free to turn in a uniform magnetic field. The loop will then come into equilibrium when its plane is inclined at
  • A
    $0^\circ $ to the direction of the field
  • B
    $45^\circ $ to the direction of the field
  • $90^\circ $ to the direction of the field
  • D
    $135^\circ $ to the direction of the field

Answer

Correct option: C.
$90^\circ $ to the direction of the field
c
In equilibrium angle between $\overrightarrow M $and $\overrightarrow B $ is zero. It is happened, when plane of the coil is perpendicular to $\overrightarrow B $

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