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Chemical Reactions and Equations — Science STD 10 — Question

CBSE BoardEnglish MediumSTD 10ScienceChemical Reactions and Equations1 Mark
MCQ
A dilute ferrous sulphate solution was gradually added to the beaker containing acidified potassium permanganate solution. The light purple colour of the solution fades and finally disappears. Which of the following is the correct explanation for the observation?
  • ✓
    $\mathrm{KMnO}_4$ is an oxidising agent, it oxidises $\mathrm{FeSO}_4$.
  • B
    $\mathrm{FeSO}_4$ acts as an oxidising agent and oxidises $\mathrm{KMnO}_4$.
  • C
    The colour disappears due to dilution: no reaction is involved.
  • D
    $\ce{KMnO}$ , is an unstable compound and decomposes in presence of $\ce{FeSO},$ to a colourless compound.
✓

Answer

Correct option: A.
$\mathrm{KMnO}_4$ is an oxidising agent, it oxidises $\mathrm{FeSO}_4$.
Potassium permanganate $\left(\mathrm{KMnO}_4\right)$ in presence of dil. $\mathrm{H}_2 \mathrm{SO}_4$,
i.e., in acidic medium acts as strong oxidising agent. In acidic medium, $\mathrm{KMnO}_4$ oxidises ferrous sulphate to ferric sulphate.
$\text{2KMnO}_4\ +\ 8\text{H}_2\text{SO}_1\ +\ 10\text{FeSO}_4\ \xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ \ \ }\ \text{K}_2\text{SO}_4\ +\ 5\text{Fe}_2(\text{SO}_4)_3\ +\ 2\text{MnSO}_4\ +\ 8\text{H}_2\text{O}$

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