A disaccharide X cannot be oxidised by bromine water. The acid hydrolysis of X leads to a laevorotatory solution. The disaccharide X is

Q: A disaccharide $X$ cannot be oxidised by bromine water. The acid hydrolysis of $X$ leads to a laevorotatory solution. The disaccharide $X$ is

a Sucrose $\xrightarrow{\mathrm{H}_3 \mathrm{O}^{+}}$Glucose + Fructose Specific rotation $+52.5^{\circ} \quad-92^{\circ}$ (mixture of products is laevorotatory) Sucrose $\xrightarrow{\mathrm{Br}_2+\mathrm{H}_2 \mathrm{O}}$ No reaction $\mathrm{BCD} \Rightarrow$ reducing sugars, will get oxidized by $\mathrm{Br}_2+\mathrm{H}_2 \mathrm{O}$

SECTION - A [CHEMISTY - MCQ]

GSEB - English Medium

A disaccharide $X$ cannot be oxidised by bromine water. The acid hydrolysis of $X$ leads to a laevorotatory solution. The disaccharide $X$ is

IIT 2023, Easy

STD 11 Science
JEE
STD 12 - 10. Biomolecules
Chemistry

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