MCQ
A Faraday is:
  • The magnitude of the charge of $1$ mole of electrons.
  • B
    The magnitude of the electric dipole.
  • C
    A fundamental constant of nature equal to $6.63 \times 10^{-34}Js/$ photon.
  • D
    A constant that accounts for the existence of ions in solution.

Answer

Correct option: A.
The magnitude of the charge of $1$ mole of electrons.
The Faraday constant represents the amount of electric charge carried by one mole, or Avogadro's number, of electrons.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

An alkyl bromide produces a single alkene when it reacts with sodium ethoxide and ethanol. This alkene undergoes hydrogenation and produces $ 2-$ methyl butane. What is the identity of the alkyl bromide
In galvanic cell, the salt bridge is used to
The cyclotrimetaphosphoric acid is
The addition of a polar solvent to a solid electrolyte results in
$2\,gm$ of benzoic acid dissolved in $25\,gm$ of benzene shows a depression in freezing point equal to $1.62\ K$ . Molal depression constant for benzene is $4.9\,K\ kg\ mol^{-1}$ . What is $\%$ degree of association of acid
Atomic number of $\text{Mn, Fe}$ and $Co$ are $25, 2$6 and $27$ respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?
$a.  {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}} $
$b.  {\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}} $
$c.  {\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}} $
$d.  {\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}} $
The form of iron having the highest carbon content is
Chlorobenzene is formed by the reaction of chlorine with benzene in the presence of $AlCl_3.$ Which of the following species attacks the benzene ring in this reaction?
The total number of isomers for a square planar complex $[M(F)(Cl)(SCN (NO_2)]$ is
$\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   Ph-C-C{{H}_{3}}\xrightarrow[HCl]{NaN{{O}_{2}}}(A)\xrightarrow[heat]{A{{C}_{2}}O}(B)\xrightarrow{{{H}_{3}}{{O}^{+}}}(C)  \\
\end{matrix}$

Product $(C)$ of the above reaction is