Question
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm . How many such tiles are required to cover a floor of area $1080 m^2$ ?
✓
Answer
Area of floor $=1080 m^2$
Base of parallelogram shaped tile (b) $=24 cm$
and corresponding height $( h )=10 cm$
Area of one tile $= b \times h =24 \times 10=240 cm^2$
$=\frac{240}{10000}=\frac{24}{100} m^2$
$\therefore$ Number of tiles required $=\frac{\frac{1050}{24}}{1000}$
$=2080 \times \frac{1000}{24}=45000$
Base of parallelogram shaped tile (b) $=24 cm$
and corresponding height $( h )=10 cm$
Area of one tile $= b \times h =24 \times 10=240 cm^2$
$=\frac{240}{10000}=\frac{24}{100} m^2$
$\therefore$ Number of tiles required $=\frac{\frac{1050}{24}}{1000}$
$=2080 \times \frac{1000}{24}=45000$
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