MCQ
A flow of $10^7$ electrons per second in a conduction wire constitutes a current of
  • A
    $1.6 \times 10^{-26} A$
  • B
    $1.6 \times 10^{12} A$
  • $1.6 \times 10^{-12} A$
  • D
    $1.6 \times 10^{26} A$

Answer

Correct option: C.
$1.6 \times 10^{-12} A$
$1.6 \times 10^{-12} A$
Hint: $ \text { I }=\frac{Q}{t}=\frac{10^7 \times 1.6 \times 10^{-19}}{1}=1.6 \times 10^{12} A . $

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