MCQ
A four-digit number is formed by using the digits 1, 2, 4, 8 and 9 without repitition. If one number is selected from those numbers, then what is the probability that it will be an odd number?
  • A
    $\frac15$
  • $\frac25$
  • C
    $\frac35$
  • D
    $\frac45$

Answer

Correct option: B.
$\frac25$
Total number of outcomes = 5 × 4 × 3 × 2 = 120

The number of favourable cases = 2(4 × 3 × 2) = 48 (i.e., odd numbers)

Therefore,

Required probability $\frac{48}{120}=\frac25$

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