- ✓$Cr{O_3},\,\,M{n_2}{O_7}$
- B$ZnO,\,\,A{l_2}{O_3}$
- C$CaO,\,\,ZnO$
- D$N{a_2}O,\,\,A{l_2}{O_3}$
$Cr{{O}_{3}}+{{H}_{2}}O\to \underset{\begin{smallmatrix}
\text{Chromic} \\
\text{acid}
\end{smallmatrix}}{\mathop{{{H}_{2}}Cr{{O}_{4}}}}\,$
$M{{n}_{2}}{{O}_{7}}+{{H}_{2}}O\to \underset{\begin{smallmatrix}
\text{Permagnic} \\
\text{acid}
\end{smallmatrix}}{\mathop{2HMn{{O}_{4}}}}\,$
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$H _2( g )+\frac{1}{2} O _2( g ) \rightarrow H _2 O (\ell)$
The work derived from the cell on the consumption of $1.0 \times 10^{-3} mol$ of $H _2( g )$ is used to compress $1.00 mol$ of a monoatomic ideal gas in a thermally insulted container. What is the change in the temperature (in $K$ ) of the ideal gas ?
The standard reduction potentials for the two half-cells are given below.
$\left. O _2( g )+4 H ^{+} \text {(aq. }\right)+4 e ^{-} \rightarrow 2 H _2 O (\ell), E ^{\circ}=1.23 V,$
$\left.2 H ^{+} \text {(aq. }\right)+2 e ^{-} \rightarrow H _2( g ), E ^{\circ}=0.00 V.$
Use $F =96500 C mol ^{-1}, R =8.314 J mol ^{-1} K ^{-1}$

