MCQ
A hydrocarbon $C_5H_{12}$ does not react with chlorine in dark but gives six monochloro compound in bright sunlight. Then hydrocarbon is
- A

- B

- C

- ✓






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$NH_4NO_3(s) \rightarrow N_2O(g) + 2H_2O(l)$
$C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} $ $B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C$
Among the given complexes, number of paramagnetic complexes is .... .
${N_2}{O_4}(g)\, \to \,2N{O_2}(g)$
Data for the given reaction is
$\Delta H = +54\,kJ$ and $E_a = + 57.2\,kJ$
.......$kJ$