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Atomic and Nuclear Physics — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsAtomic and Nuclear Physics1 Mark
MCQ
A hydrogen atom (ionisation potential $13.6 eV$ ) makes a transition from third excited state to first excited state. The energy of the photon emitted in the process is [MNR 1995]
  • A
    $1.89 eV$
  • ✓
    $2.55 eV$
  • C
    $12.09 eV$
  • D
    $12.75 eV$
✓

Answer

Correct option: B.
$2.55 eV$
Energy released $=13.6\left[\frac{1}{(2)^2}-\frac{1}{(4)^2}\right]=2.55 \mathrm{eV}$

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