MCQ
A hydrogen electrode is immersed in a solution with $pH = 0\,(HCl)$. By how much will the potential (reduction) change if an equivalent amount of $NaOH$ is added to the solution.

(Take $pH_2 = 1\,atm$ ), $T = 298\,K$.

  • A
    increase by $0.41\,V$
  • B
    increase by $59\,mV$
  • decrease by $0.41\,V$
  • D
    decrease by $59\,mV$

Answer

Correct option: C.
decrease by $0.41\,V$
c
$pH$ changes from $0$ to $7$.

$\therefore $  $[H^+]$  changes from $1$ to $10^{-7}\,M$

Accordingly ${{E}_{red.}}=\,\frac{-\,0.059}{n}\,\log \,\frac{1}{[{{H}^{+}}]}$

                             $ = \,0.059\,\,\log \,{10^{ - 7}}$

i.e., $0.059\times (-7)\,=\,-0.41\,volts$

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