(Take $pH_2 = 1\,atm$ ), $T = 298\,K$.
- Aincrease by $0.41\,V$
- Bincrease by $59\,mV$
- ✓decrease by $0.41\,V$
- Ddecrease by $59\,mV$
(Take $pH_2 = 1\,atm$ ), $T = 298\,K$.
$\therefore $ $[H^+]$ changes from $1$ to $10^{-7}\,M$
Accordingly ${{E}_{red.}}=\,\frac{-\,0.059}{n}\,\log \,\frac{1}{[{{H}^{+}}]}$
$ = \,0.059\,\,\log \,{10^{ - 7}}$
i.e., $0.059\times (-7)\,=\,-0.41\,volts$
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$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2} - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\
{\,\,OTs\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OTs}
\end{array}\xrightarrow[{(ii)\,KOH}]{{(i)\mathop {\,S}\limits^ \ominus H\,(one\,\,equivalent)}}[X]$
$[X]$ will be :
The total number of methyl $\left(- CH _3\right)$ group($s$) in compound $S$ is. . . .

(Image)
$IUPAC$ name of Compound $A$ is $4-$ chloro-$1$, $3$-dinitrobenzene:
(Image)
$IUPAC$ name of Compound $B$ is
$4$-ethyl-$2$-methylaniline.
In the light of the above statements, choose the most appropriate answer from the options given below: