A = [ * 20 c 5& - 3 2&4 ]and B = [ * 20 c 6& - 4 3&6 ], then A - … - Vidyadip

MCQ

$A = \left[ {\begin{array}{*{20}{c}}5&{ - 3}\\2&4\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}6&{ - 4}\\3&6\end{array}} \right],$ then $A - B = $

A
$\left[ {\begin{array}{*{20}{c}}{11}&{ - 7}\\5&{10}\end{array}} \right]$
✓
$\left[ {\begin{array}{*{20}{c}}{ - 1}&{{\rm{ }}1}\\{ - 1}&{ - 2}\end{array}} \right]$
C
$\left[ {\begin{array}{*{20}{c}}{11}&7\\5&{ - 10}\end{array}} \right]$
D
$\left[ {\begin{array}{*{20}{c}}{12}&{ - 7}\\5&{ - 10}\end{array}} \right]$

✓

Answer

Correct option: B.

$\left[ {\begin{array}{*{20}{c}}{ - 1}&{{\rm{ }}1}\\{ - 1}&{ - 2}\end{array}} \right]$

b
(b) $A = \left[ {\begin{array}{*{20}{c}}5&{ - 3}\\2&4\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}6&{ - 4}\\3&6\end{array}} \right]$,

$\therefore$ $A - B = \left[ {\begin{array}{*{20}{c}}{ - 1}&{\,\,\,1}\\{ - 1}&{ - 2}\end{array}} \right]$.

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