MCQ
A light has amplitude $A$ and angle between analyser and polariser is $ 60^o .$  Light is reflected by analyser has amplitude
  • A
    $A\sqrt 2 $
  • B
    $A/\sqrt 2 $
  • C
    $\sqrt 3 A/2$
  • $A/2$

Answer

Correct option: D.
$A/2$
d
(d)The amplitude will be$A\cos {60^o} = A/2$

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