MCQ
A long spring is stretched by $2\ cm.$ Its potential energy is $V.$ If the spring is stretched by $10\ cm,$ its potential energy would be:
- A$\frac{\text{v}}{25}$
- B$\frac{\text{v}}{5}$
- C$5V$
- ✓$25V$
✓
Answer
Correct option: D.
$25V$
Potential energy $\propto\text{x}^2$ When $\times$ becomes $5$ times, $P.E.$ becomes $25$ times.
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