MCQ
A man does a given amount of work in $10 \mathrm{sec}$. Another man does the same amount of work in $20 \mathrm{sec}$. The ratio of the output power of first man to the second man is
- A1
- B$1 / 2$
- ✓$2 / 1$
- DNone of these
✓
Answer
Correct option: C.
$2 / 1$
Power $=\frac{W}{t}$. If $W$ is constant then $P \propto \frac{1}{t}$
i.e$(\frac{P_1}{P_2})=\frac{t_2}{t_1}=\frac{20}{10}=\frac{2}{1}$
i.e$(\frac{P_1}{P_2})=\frac{t_2}{t_1}=\frac{20}{10}=\frac{2}{1}$
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