A metal X forms a salt XSO _4. The salt XSO _4 forms a clear solu… - Vidyadip

Question

A metal X forms a salt $XSO _4$. The salt $XSO _4$ forms a clear solution in water which reacts with sodium hydroxide solution to form a blue precipitate Y .
Metal X is used in making electric wire and alloys like brass.
a. What do you think metal $X$ could be?
b. Write the name, formula and colour of salt $XSO _4$.
c. What is the blue precipitate Y ?
d. Write a chemical equation of the reaction which takes place when salt $XSO _4$ reacts with sodium hydroxide solution. Give the state symbols of all the reactants and products which occur in the above equation.

✓

Answer

a. Metal X could be copper (Cu).
b. The salt $XSO _4$ is copper sulphate its formula is $CuSO _4$ and it is blue in colour.
c. Copper hydroxide $\left[ Cu ( OH )_2\right]$ is the blue precipitate.
d. $CuSO _4( aq )+2 NaOH ( aq ) \longrightarrow Cu ( OH )_2(s)+ Na _2 SO _4( aq )$

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