A moving coil galvanometer has 150 equal divisions. Its current s… - Vidyadip

MCQ

A moving coil galvanometer has $150$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1\, volt$, the resistance in $ohms$ needed to be connected in series with the coil will be

A
$99995$
B
$9995$
C
${10^3}$
D
${10^5}$

✓

Answer

Voltage sensitivity $ = \frac{{{\rm{Current \,sensitivity}}}}{{{\rm{Resistance\, of \,galvanometer}}\,{\rm{G}}}}$

$ \Rightarrow $ $G = \frac{{10}}{2} = 5\,\Omega $.

Here ${i_g} = $ Full scale deflection current $ = \frac{{150}}{{10}} = 15\,mA$.

$V =$ Voltage to be measured $= 150 × 1 = 150 \,V.$

Hence $R = \frac{V}{{{i_g}}} - G = \frac{{150}}{{15 \times {{10}^{ - 3}}}} - 5 = 9995\,\Omega $.

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