MCQ
A nucleus $_n{X^m}$ emits one $\alpha$ particle and two $\beta$ particles. The resulting nucleus is
- ✓$_n{X^{m - 4}}$
- B$_{n - 2}{Y^{m - 4}}$
- C$_{n - 4}{Z^{m - 4}}$
- D$_{n - 1}{Z^{m - 4}}$
✓
Answer
Correct option: A.
$_n{X^{m - 4}}$
a
When an alpha particle $({}_2^4He)$ is emitted, the mass number and the atomic number of the daughter nucleus decreases by four and two respectively. When a beta particle $\left(\beta^{-}\right)$ is emitted, the atomic number of the daughter nucleus increases by one but the mass number remains the
same.
When an alpha particle $({}_2^4He)$ is emitted, the mass number and the atomic number of the daughter nucleus decreases by four and two respectively. When a beta particle $\left(\beta^{-}\right)$ is emitted, the atomic number of the daughter nucleus increases by one but the mass number remains the
same.
$\therefore \quad _n^mX\xrightarrow{\alpha }{}_{n - 2}^{m - 4}Y\xrightarrow{{2{\beta ^ - }}}{}_n^{m - 4}X$
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