Question
A parallel plate capacitor is charged. If the plates are pulled apart:

Answer

  1. The potential difference increases.
Explanation:
Capacitance of a parallel plate capacitor.
$\text{C}=ε0\text{AdC}=ε0\text{Ad}$
A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same.
$\because$ Potentialdifference = ChargeCapacitance∵Potentialdifference = ChargeCapacitance.
$\therefore$ potential difference increases.

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