Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsElectrostatic Potential and Capacitance1 Mark
Question
A parallel plate capacitor is charged. If the plates are pulled apart:
✓
Answer
The potential difference increases.
Explanation:
Capacitance of a parallel plate capacitor.
$\text{C}=ε0\text{AdC}=ε0\text{Ad}$
A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same.
$\because$ Potentialdifference = ChargeCapacitance∵Potentialdifference = ChargeCapacitance.
$\therefore$ potential difference increases.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.