MCQ
A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed
- A100 m
- B150 m
- ✓200 m
- D250 m
✓
Answer
Correct option: C.
200 m
(C)
$R=\frac{u^2 \sin 2 \theta}{g} \Rightarrow R \propto u^2$.So if the speed of projection is doubled, the range will become four times,4 x 50 = 200m
$R=\frac{u^2 \sin 2 \theta}{g} \Rightarrow R \propto u^2$.So if the speed of projection is doubled, the range will become four times,4 x 50 = 200m
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A turn table which is rotating uniformly has a particle placed on it. As seen from the ground, the particle goes in a circle with speed 20 cm/s and acceleration $20 cm / s ^2$ The particle is now shifted to a new position where radius is half of the original value. The new values of speed and acceleration will be
→Two bodies of masses $m_1$ and $m_2$ are separated by a distance R. The distance of the centre of mass of the bodies from the mass $m_1$ is
→In inelastic collision,
The ozone layer in the atmosphere absorbs
A place where the horizontal component of Earth’s magnetic field is zero lies at
Three vectors $\vec{A}, \vec{B}$ and $\vec{C}$ satisfy the relation $\vec{A} \cdot \vec{B}=0$ and $\vec{A} \cdot \vec{C}=0$, then $\vec{A}$ is parallel to
→If the length of the second's hand in a stop clock is 3 cm, the angular velocity and linear velocity of the tip is
The minimum number of numerically equal vectors whose vector sum can be zero is
Sound of frequency $1000 Hz$ from a stationary source is reflected from an object approaching the source at $30 m s ^{-1}$, back to a stationary observer located at the source. The speed of sound in air is $330 m s ^{-1}$. The frequency of the sound heard by the observer is
→