A particle executes simple harmonic motion with an amplitude of $4 \,cm$. At the mean position the velocity of the particle is $10\, cm/s$. The distance of the particle from the mean position when its speed becomes $5 \,cm/s$ is
  • A$\sqrt 3 \,cm$
  • B$\sqrt 5 \,cm$
  • C$2(\sqrt 3 )\,cm$
  • D$2(\sqrt 5 )\,cm$
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