A particle executes simple harmonic motion with an amplitude of $5\, cm$. When the particle is at $4\, cm$ from the mean position, the magnitude of its velocity is $SI\,units$ is equal to that of its acceleration. Then, its periodic time in seconds is
  • A$\frac{4\pi}{3}$
  • B$\frac{3}{8}\pi$
  • C$\frac{8\pi}{3}$
  • D$\frac{7}{3}\pi$
JEE MAIN 2019, Medium
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