A particle executing a simple harmonic motion of period $2\ s$ . When it is at its extreme displacement from its mean position, it receives an additional energy equal to what it had in its mean position. Due to this , in its subsequent motion,
Aits amplitude will change and become equal to $\sqrt 2 $ times its previous amplitude
Bits periodic time will become doubled $i.e.$ $4\ s$
C
its potential energy will be decreased
D
it will continue to execute simple harmonic motion of the same amplitude and period as before receiving the additional energy.
Medium
Download our app for free and get started
Aits amplitude will change and become equal to $\sqrt 2 $ times its previous amplitude
a Its new amplitude is $\sqrt{2}$ times of previous amplitude.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
The displacement y of a particle executing periodic motion is given by $y = 4{\cos ^2}(t/2)\sin (1000t)$. This expression may be considered to be a result of the superposition of ........... independent harmonic motions
Two particles undergo $SHM$ along parallel lines with the same time period $(T)$ and equal amplitudes. At a particular instant, one particle is at its extreme position while the other is at its mean position. They move in the same direction. They will cross each other after a further time
A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ${\omega _0}$ - An external force $F (t)$ proportional to $\cos \omega \,t((\omega \ne {\omega _0})$ is applied to the oscillator. The time displacement of the oscillator will be proportional to
A particle is executing simple harmonic motion with a time period $T.$ At time $t = 0$, it is at its position of equilibrium. The kinetic energy-time graph of the particle will look like
A body is in simple harmonic motion with time period half second $(T\, = 0.5\, s)$ and amplitude one $cm\, (A\,= 1\, cm)$. Find the average velocity in the interval in which it moves form equilibrium position to half of its amplitude .... $cm/s$
A particle of mass $10 \,g$ is undergoing $S.H.M.$ of amplitude $10 \,cm$ and period $0.1 \,s$. The maximum value of force on particle is about ............ $N$
Two pendulum have time periods $T$ and $5T/4$. They start $SHM$ at the same time from the mean position. After how many oscillations of the smaller pendulum they will be again in the same phase
A simple pendulum with iron bob has a time period $T$. The bob is now immersed in a non-viscous liquid and oscillated. If the density of liquid is $\frac{1}{12}$ th that of iron, then new time period will be