A particle executing simple harmonic motion of amplitude $5\, cm$ has maximum speed of $31.4\, cm/s$. The frequency of its oscillation is ..... $Hz$
AIPMT 2005, Easy
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(d) ${v_{\max }} = a\omega = a \times 2\pi n$
==> $n = \frac{{{v_{\max }}}}{{2\pi a}} = \frac{{31.4}}{{2 \times 3.14 \times 5\times 10^{-2}}} = 1\,Hz$
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