A particle executing simple harmonic motion with amplitude of $0.1 \,m$. At a certain instant when its displacement is $0.02 \,m$, its acceleration is $0.5 \,m/s^2$. The maximum velocity of the particle is (in $m/s$)
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(c) Acceleration $A = {\omega ^2}y$
$ \Rightarrow \omega = \sqrt {\frac{A}{y}} = \sqrt {\frac{{0.5}}{{0.02}}} = 5$
Maximum velocity ${v_{\max }} = a\omega = 0.1 \times 5 = 0.5$
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