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STD 11 - 4.1 , newtons laws of motion — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 4.1 , newtons laws of motion4 Marks
MCQ
A particle is acted upon by a force whose  component's variations with time are shown in diagrams. Then the magnitude of change in momentum of the particle in $0.1\,\,sec$ will be :-
  • A
    $2\,\,kg\, m\,/\,sec$
  • B
    $10\,\,kg\, m\,/\,sec$
  • C
    $12\,\,kg\, m\,/\,sec$
  • ✓
    $5\sqrt 2\,\,kg\, m\,/\,sec$
✓

Answer

Correct option: D.
$5\sqrt 2\,\,kg\, m\,/\,sec$
d
$\Delta p_{x}=3 \mathrm{NS}$

$\Delta p_{y}=4 \mathrm{NS}$

$\Delta p_{z}=-5 N S$

$\Delta p=\sqrt{3^{2}+4^{2}+5^{2}}=5 \sqrt{2} \mathrm{NS}$

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