Question
A particle is acted upon by a force whose component's variations with time are shown in diagrams. Then the magnitude of change in momentum of the particle in $0.1\,\,sec$ will be :-
✓
Answer
$\Delta p_{x}=3 \mathrm{NS}$
$\Delta p_{y}=4 \mathrm{NS}$
$\Delta p_{z}=-5 N S$
$\Delta p=\sqrt{3^{2}+4^{2}+5^{2}}=5 \sqrt{2} \mathrm{NS}$
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