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Find the ratio of time periods of two identical springs if they are first joined in series $\&$ then in parallel $\&$ a mass $m$ is suspended from them :
A simple pendulum with iron bob has a time period $T$. The bob is now immersed in a non-viscous liquid and oscillated. If the density of liquid is $\frac{1}{12}$ th that of iron, then new time period will be
An object of mass $0.2\ kg$ executes simple harmonic along $X-$ axis with frequency of $\frac{{25}}{\pi } Hz$ . At the position $x$ = $0.04\ m$ , the object has kinetic energy of $0.5\ J$ and potential energy of $0.4\ J$ amplitude of oscillation in meter is equal to
If $< E >$ and $< U >$ denote the average kinetic and the average potential energies respectively of mass describing a simple harmonic motion, over one period, then the correct relation is
A particle undergoing simple harmonic motion has time dependent displacement given by $x(t)\, = \,A\,\sin \,\frac{{\pi t}}{{90}}$. The ratio of kinetic to potential energy $o$ the particle at $t=210\,s$ will be