A particle is performing simple harmonic motion
$(i)$ its velocity-displacement graph is parabolic in nature
$(ii)$ its velocity-time graph is sinusoidal in nature
$(iii)$ its velocity-acceleration graph is elliptical in nature
Correct answer is
Medium
Download our app for free and get startedPlay store
$(i)$ $\mathrm{v}=\omega \sqrt{\mathrm{A}^{2}-\mathrm{x}^{2}}$ $(ii)$ $\mathrm{v}=\mathrm{A} \omega \cos \omega \mathrm{t}$

$\mathrm{v}=\mathrm{A} \omega \cos \omega \mathrm{t} ; \mathrm{a}=\mathrm{A} \omega^{2} \sin \omega \mathrm{t}$

$\Rightarrow \frac{v^{2}}{A^{2} \omega^{2}}+\frac{a^{2}}{A^{2} \omega^{4}}=1$

$(ii)$ and $(iii)$ are correct

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    This is the position time graph of a mass on spring. What can you say about the velocity and force at the instant indicated by dashed line ? (positive direction is to the right)
    View Solution
  • 2
    pendulum made of a uniform wire of cross sectional area $A$ has time period $T$. When an additional mass $M$ is added to its bob, the time period changes to $T_M$. If the Young's modulus of the material of the wire is $Y$ then $\frac{1}{Y}$ is equal to : ($g$ = gravitational acceleration)
    View Solution
  • 3
    The length of a seconds pendulum at a height $h=2 R$ from earth surface will be.(Given: $R =$ Radius of earth and acceleration due to gravity at the surface of earth $g =\pi^{2}\,m / s ^{-2}$ )
    View Solution
  • 4
    For a body executing $S.H.M. :$

    $(a)$ Potential energy is always equal to its $K.E.$

    $(b)$ Average potential and kinetic energy over any given time interval are always equal.

    $(c)$ Sum of the kinetic and potential energy at any point of time is constant.

    $(d)$ Average $K.E.$ in one time period is equal to average potential energy in one time period.

    Choose the most appropriate option from the options given below:

    View Solution
  • 5
    A particle is executing simple harmonic motion $(SHM)$ of amplitude $A,$ along the $x-$ axis, about $x = 0.$ When its potential energy $(PE)$ equals kinetic energy $(KE),$ the position of the particle will be
    View Solution
  • 6
    In figure $(A),$ mass ' $2 m$ ' is fixed on mass ' $m$ ' which is attached to two springs of spring constant $k$. In figure $(B),$ mass ' $m$ ' is attached to two spring of spring constant ' $k$ ' and ' $2 k$ '. If mass ' $m$ ' in $(A)$ and $(B)$ are displaced by distance ' $x$ ' horizontally and then released, then time period $T_{1}$ and $T_{2}$ corresponding to $(A)$ and $(B)$ respectively follow the relation.
    View Solution
  • 7
    The motion of a mass on a spring, with spring constant ${K}$ is as shown in figure. The equation of motion is given by $x(t)= A sin \omega t+ Bcos\omega t$ with $\omega=\sqrt{\frac{K}{m}}$ Suppose that at time $t=0$, the position of mass is $x(0)$ and velocity $v(0)$, then its displacement can also be represented as $x(t)=C \cos (\omega t-\phi)$, where $C$ and $\phi$ are
    View Solution
  • 8
    The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are $2\,m/s$ and $4\,m/{s^2}.$ Then angular velocity will be ..... $rad/sec$
    View Solution
  • 9
    Two springs of constant ${k_1}$and ${k_2}$are joined in series. The effective spring constant of the combination is given by
    View Solution
  • 10
    A loaded vertical spring executes $S.H.M.$ with a time period of $4\; sec$. The difference between the kinetic energy and potential energy of this system varies with a period of ........$sec$
    View Solution