Question
A particle on a rotating disc have initial and final angular positions are
- -2 rad, +6 rad.
- -4 rad, -8 rad.
- 6 rad, -2 rad.
✓
Answer
- Angular displacement is $\Delta\theta=\theta_{\text{f}}-\theta_{\text{i}}=6-(-2)=8\text{rad}$
- $\Delta\theta=\theta_{\text{f}}-\theta_{\text{i}}$
$=-8\text{rad}-(-4\text{rad})=-4\text{rad}$
- $\Delta\theta=-2\text{rad}-(+6\text{rad})=-8\text{rad}$
In cascs (ii) ad (iii), angular displacement is negative.
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