A particle performs $S.H.M.$ of amplitude $A$ with angular frequency $\omega$  along a straight line. Whenit is at a distance  $\frac{{\sqrt 3 }}{2}$ $A$  from mean position, its kinetic energy gets increased by an amount $\frac{1}{2}m{\omega ^2}{A^2}$  due to an impulsive force. Then its new amplitude becomes
  • A$\frac{{\sqrt 5 }}{2}A$
  • B$\frac{{\sqrt 3 }}{2}A$
  • C$\sqrt 2$ $A$
  • D$\sqrt 5$ $A$
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