MCQ
A pendulum clock keeps correct time at $0^{\circ} \mathrm{C}$. Its mean coefficient of linear expansions is $\alpha /{ }^{\circ} \mathrm{C}$, then the loss in seconds per day by the clock if the temperature rises by $t^{\circ} \mathrm{C}$ is
- A$\frac{\frac{1}{2} \alpha t \times 864000}{1-\frac{\alpha t}{2}}$
- ✓$\frac{1}{2} \alpha t \times 86400$
- C$\frac{\frac{1}{2} \alpha t \times 86400}{\left(1-\frac{\alpha t}{2}\right)^2}$
- D$\frac{\frac{1}{2} \alpha t \times 86400}{1+\frac{\alpha t}{2}}$