- AIntensity
- ✓Frequency
- CWavelength
- Dnone
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


$I. n = 4,l = 2,m_l = -2, m_s = -1/ 2$
$II. n = 3,l = 2, m_l = 1,m_s = +1/ 2$
$III. n = 4,l = 1, m_l = 0, m_s = +1/ 2$
$IV. n = 3,l = 1, m_l = 1; m_s = -1/ 2$
The correct order of their increasing energies will be

$2 \mathrm{Fe}_{(\mathrm{s})}+\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}, \Delta \mathrm{H}^{\mathrm{o}}=-822 \mathrm{~kJ} / \mathrm{mol}$
$\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{(\mathrm{g})}, \Delta \mathrm{H}^{\mathrm{o}}=-110 \mathrm{~kJ} / \mathrm{mol}$
Then enthalpy change for following reaction
$3\mathrm{C}_{(\mathrm{s})}+\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})} \rightarrow 2 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{CO}_{(\mathrm{g})}$