MCQ
A pole casts a shadow of length $2\sqrt{3}\text{m}$ on the ground when the sun's elevation is $60^\circ$ . The height of the pole is :
- ✓$6\text{m}$
- B$4\sqrt{3}\text{m}$
- C$12\text{m}$
- D$3\text{m}$
✓
Answer
Correct option: A.
$6\text{m}$
Let the height of the pole be $h$ metres.
Then, $\frac{\text{h}}{2\sqrt3}=\tan60^\circ=\sqrt{3}$
$\Rightarrow\text{h}=(2\sqrt{3}\times\sqrt{3})=6.$
Then, $\frac{\text{h}}{2\sqrt3}=\tan60^\circ=\sqrt{3}$
$\Rightarrow\text{h}=(2\sqrt{3}\times\sqrt{3})=6.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The mean of the data when$\sum\text{f}_\text{i}\text{d}_{\text{i}}=-500,\sum\text{f}_\text{i} =100 $ and $ \text{a}=125$ is :
→If $\left(a^2+b^2\right) x^2+2(a c+b d) x+c^2+d^2=0$ has no real roots, then
→If the difference of mode and median of a data is 24, then the difference of median and mean is
The sum of first $40$ positive integers divisible by $6$ is.
→The roots of the equation $x^2-2 x-\left(r^2-1\right)=0$ are
→The mean of n observations is $\bar{\text{x}}$ If the first observation is increased by 1, the second by 2, the third by 3, and so on, then the new mean is:
→The quadratic equation $x^2+x+1=0$ has ____________ roots.
→O is the point of intersection of two chords AB and CD of a circle.
If $\angle B O C=80^{\circ}$ and $O A=O D$ then $\triangle O D A$ and $\triangle O B C$ are
→If $\angle B O C=80^{\circ}$ and $O A=O D$ then $\triangle O D A$ and $\triangle O B C$ are
The roots of the equation $8 x^2-22 x-21=0$ are
→If $7\tan\theta=4$ then $\frac{(7\sin\theta-3\cos\theta)}{(7\sin\theta+3\cos\theta)} =?$
→