A potential divider circuit is shown in figure. The output voltage $V_0$ is
JEE MAIN 2024, Diffcult
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$ R_{e q}=4000 \Omega $
$ i=\frac{4}{4000}=\frac{1}{1000} \mathrm{~A} $
$ V_0=i \cdot R=\frac{1}{1000} \times 500=0.5 \mathrm{~V}$
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