A potentiometer consists of a wire of length $4\, m$ and resistance $10 \,\Omega$. It is connected to cell of $emf$ $2\, V$. The potential difference per unit length of the wire will be ............ $V/m$
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Potential difference per unit length $ = \frac{V}{L} = \frac{2}{4} = 0.5\,V/m$
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