A potentiometer consists of a wire of length $4\, m$ and resistance $10\,\Omega $. It is connected to a cell of $e.m.f.$ $2\, V$. The potential difference per unit length of the wire will be ............. $V/m$
AIPMT 1999, Easy
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Since potential difference for full length of wire $=$ $2\, V$
$P.D.$ per unit length of wire $ = \frac{2}{4} = 0.5\,\frac{V}{m}$
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