- A$\frac {u_0^2}{2g}$
- ✓$\frac {2u_0v_0}{g}$
- C$\frac {v_0^2}{2g}$
- D$\frac {4u_0v_0}{g}$
$\overrightarrow{ U }=u_0 \hat{1}+v_0 \hat{j}$
$u_0=u \cos \theta \ldots \ldots .1$
$v_0=v \sin \theta \ldots \ldots . .2$
Since,
$R =\frac{ u ^2 2 \sin 2 \theta}{ g }$
$R =\frac{ u ^2 2(\sin \theta \cdot \cos \theta)}{ g } \ldots \ldots$
Substituting the value of equation 1,2 in eqyuation 3 then we get,
$R =\frac{2 u _0 v _0}{ g }$
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$1.$ Which of the following statement regarding the angular speed about the istantaneous axis (passing through the centre of mass) is correct?
$(A)$ It is $\sqrt{2} \omega$ for boht the cases
$(B)$ it is $\omega$ for case $(a)$; and $\frac{w}{\sqrt{2}}$ for case $(b)$.
$(C)$ It is $\omega$ for case $(a)$; and $\sqrt{2} \omega$ for case $(b)$.
$(D)$ It is $\omega$ for both the cases
$2.$ Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct?
$(A)$ It is vertical for both the cases $(a)$ and $(b)$.
$(B)$ It is verticle for case $(a)$; and is at $45^{\circ}$ to the $x-z$ plane and lies in the plane of the disc for case $(b)$
$(C)$ It is horizontal ofr case $(a)$; and is at $45^{\circ}$ to the $x - z$ plane and is normal to the plane of the disc for case $(b)$.
$(D)$ It is vertical of case $(a)$; and is at $45^{\circ}$ to the $x - z$ plane and is normal to the plane of the disc for case $(b)$.
Give the answer question $1$ and $2.$
Step $1$ It is first compressed adiabatically from volume $V_{1}$ to $1 \;m ^{3}$.
Step $2$ Then expanded isothermally to volume $10 \;m ^{3}$.
Step $3$ Then expanded adiabatically to volume $V _{3}$.
Step $4$ Then compressed isothermally to volume $V_{1}$. If the efficiency of the above cycle is $3 / 4$, then $V_{1}$ is ............ $m^3$