MCQ
A projectile is projected with velocity u making an angle $\theta$ with the horizontal, the equation of the path of the projectile is given by
- A$x=(\tan \theta) y-\left(\frac{g}{2 u^2 \cos ^2 \theta}\right) y^2$
- B$y=(\tan \theta) x-\left(\frac{g}{2 u \cos \theta}\right) x^2$
- C$y=(\tan \theta) x-\left(\frac{g}{2 u^2 \cos \theta}\right) x^2$
- ✓$y=(\tan \theta) x-\left(\frac{g}{2 u^2 \cos ^2 \theta}\right) x^2$
