MCQ
A projectile is projected with velocity u making an angle $\theta$ with the horizontal, the equation of the path of the projectile is given by
  • A
    $x=(\tan \theta) y-\left(\frac{g}{2 u^2 \cos ^2 \theta}\right) y^2$
  • B
    $y=(\tan \theta) x-\left(\frac{g}{2 u \cos \theta}\right) x^2$
  • C
    $y=(\tan \theta) x-\left(\frac{g}{2 u^2 \cos \theta}\right) x^2$
  • $y=(\tan \theta) x-\left(\frac{g}{2 u^2 \cos ^2 \theta}\right) x^2$

Answer

Correct option: D.
$y=(\tan \theta) x-\left(\frac{g}{2 u^2 \cos ^2 \theta}\right) x^2$
D

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