Question

A proton accelerated by a potential difference 500 KV moves though a transverse magnetic field of 0.51T as shown in figure. The angle θ through which the proton deviates from the initial direction of its motion is

(a) 15°

(b) 30°

(c) 45°

(d) 60°

Answer

(b) 30°

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A charge q coulomb moves in a circle at n revolutions per second and the radius of the circle is r metre. Then magnetic field at the centre of the circle is

(a)  N/amp/metre

(b)  N/amp/metre

(c) N/amp/metre

(d)  N/amp/metre

The minimum wavelength of photon is 5000 Å, its energy will be

(a) 2.5 eV

(b) 50 V

(c) 5.48 eV

(d) 7.48 eV

If the frequency of EM radiations is halved then the energy of EM radiation will become:
In an electric circuit containing a battery, the charge (assumed positive) inside the battery:
  1. Always goes from the positive terminal to the negative terminal.
  2. May go from the positive terminal to the negative terminal.
  3. Always goes from the negative terminal to the positive terminal
  4. Does not move.

Two wires of the same material and equal length are joined in parallel combination.  If one of them has half the thickness of the other and the thinner wire has a resistance of 8 ohms, the resistance of the combination is equal to

(a)  

(b)  

(c)  

(d)  

Mark the incorrect statement.
A proton and an alpha particle both enter a region of uniform magnetic field B, moving at right angles to field B. If the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is 1 MeV the energy acquired by the alpha particle will be:

In an hydrogen atom, the electron revolves around the nucleus in an orbit of radius 0.53 . Then the electrical potential produced by the nucleus at the position of the electron is

(a) – 13.6 V

(b) – 27.2 V

(c) 27.2 V  

(d) 13.6 V

The SI unit of electrical energy is ____________?

A convex lens of focal length 25 cm and a concave lens of focal length 10 cm are joined together.  The power of the combination will be

(a) – 16 D

(b) + 16 D

(c) – 6 D  

(d) + 6 D