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$\lambda_\text{e}=\lambda_\text{p}.$
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$\lambda_\text{e}<\lambda_\text{p}.$
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$\lambda _\text{e}>\lambda_\text{p}.$
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The relation between
$\lambda_\text{e}=\lambda_\text{p}.$
$\lambda_\text{e}<\lambda_\text{p}.$
$\lambda _\text{e}>\lambda_\text{p}.$
The relation between
Explanation:
Let me and mp be the masses of electron and proton, respectively.
Let the applied potential difference be V.
Thus, the de-Broglie wavelength of the electron,
$\lambda=\frac{\text{h}}{\sqrt{2\text{m}_\text{e}\text{eV}}}\dots(1)$
And de-Broglie wavelength of the proton,
$\lambda=\frac{\text{h}}{\sqrt{2\text{m}_\text{p}\text{eV}}}\dots(2)$
Dividing equation (2) by equation (1), we get:
$\frac{\lambda_\text{p}}{\lambda_\text{e}}=\frac{\sqrt{\text{m}_\text{e}}}{\sqrt{\text{m}_\text{p}}}$
$\text{m}_\text{e}<\text{m}_\text{p}$
$\therefore\frac{\lambda_\text{p}}{\lambda_\text{e}}<1$
$\Rightarrow\lambda_ \text{p}<\lambda_\text{e}$
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The force acting between proton and proton inside the nucleus is
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(a) Coulombic |
(b) Nuclear |
(c) Both |
(d) None of these |
Peltier coefficient for the junction of a pair of metals is proportional to
|
(a) T absolute temperature of the junction |
|
(b) Square of absolute temperature of the junction |
|
(c) |
|
(d) |
and
represent mass of neutron and proton respectively. If an element having atomic mass M has N-neutron and Z-proton, then the correct relation will be
|
(a) |
(b) |
(c) |
(d) |
Which is not true with respect to the cathode rays
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(a) A stream of electrons |
(b) Charged particles |
|
(c) Move with speed same as that of light |
(d) Can be deflected by magnetic fields |
If the ratio of amplitude of two waves is 4 : 3, then the ratio of maximum and minimum intensity is
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(a) 16 : 18 |
(b) 18 : 16 |
(c) 49 : 1 |
(d) 94 : 1 |
$0$
$\delta$
$2\delta$
$3\delta$