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4. Moving charges and magnetism — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics4. Moving charges and magnetism1 Mark
MCQ
A proton is moves on circular path with its constant angular speed then correct relation between its magnetic moment and angular momentum 
  • A
    $\vec M =  - \frac{{e\vec L}}{{2{m_p}}}$
  • ✓
    $\vec M =   \frac{{e\vec L}}{{2{m_p}}}$
  • C
    $\vec M =  \left( {\frac{{2e}}{{{m_p}}}} \right)\vec L$
  • D
    $\vec M =  - \left( {\frac{{2e}}{{{m_p}}}} \right)\vec L$
✓

Answer

Correct option: B.
$\vec M =   \frac{{e\vec L}}{{2{m_p}}}$
b

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