Given dimensions of the bigger rectangle are $6\ cm$ and $5\ cm$
$\therefore$ Area of bigger rectangle $=6 \mathrm{~cm} \times 5 \mathrm{~cm}=30 \mathrm{~cm}^2[\because$ area of rectangle $=$ length $\times$ breadth $]$
Also given, dimensions of the smaller rectangle are $3\ cm$ and $2\ cm$
$\therefore$ Area of smaller rectangle $=3 \mathrm{~cm} \times 2 \mathrm{~cm}=6 \mathrm{~cm}^2$
$\therefore$ Area of remaining sheet of paper $=$ Area of bigger rectangle - Area of smaller rectangle $=(30-6) \mathrm{cm}^2=24 \mathrm{~cm}^2$
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