Question
A rectangular tank is 80m long and 25m broad. Water flows into it through a pipe whose cross-section is 25cm2, at the rate of 16km per hour. How much the level of the water rises in the tank in 45 minutes?

Answer

Consider 'h' be the rise in water level.
Volume of water in rectangular tank = 8000 × 2500 × h cm2
Cross-sectional area of the pipe = 25cm2
Water coming out of the pipe forms a cuboid of base area 25cm2 and length equal to the distance travelled in 45 minutes with the speed 16km/hour
i.e., length = Length $=16000\times100\times\frac{45}{60}\text{cm}$
Therefore, The Volume of water coming out pipe in 45 minutes $=25\times16000\times100\times\Big(\frac{45}{60}\Big)$
Now, volume of water in the tank = Volume of water coming out of the pipe in 45 minutes
$\Rightarrow8000\times2500\times\text{h}=16000\times100\times\frac{45}{60}\times25$
$\Rightarrow\text{h}=\frac{25\times16000\times100\times45}{60\times8000\times2500}=1.5\text{cm}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free