A relation from C to R is defined by x y |x|=y. Which one is corr… - Vidyadip

MCQ

A relation $\phi$ from $C$ to $R$ is defined by $\text{x }\phi\text{ y}\Leftrightarrow|\text{x}|=\text{y.}$ Which one is correct?

A
$(2+3\text{i})\phi13$
B
$3\phi(-3)$
C
$(1+\text{i})\phi2$
✓
$\text{i}\phi1$

✓

Answer

Correct option: D.

$\text{i}\phi1$

$\because\ |2+3\text{i}|=\sqrt{13}\neq13$
$|3|\neq-3$
$|1+\text{i}|=\sqrt{2}\neq2$
and $|\text{i}|=1$
So, $(\text{i, }1)\in\phi$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Relations and Functions→Relations and Functions — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The solution of $\frac{{dy}}{{dx}} = \left( {\frac{{ax + b}}{{cy + d}}} \right)$ represents a parabola if

A line makes the same angle $\theta$ with each of thex and $z$ axis. If the angle $\beta$ which it makes with $y-$ axis is such that $\sin^2\beta=3\sin^2\theta$ then $\cos^2\theta$ equals:

Let $X$ be a random variable such that the probability function of a distribution is given by $P(X=$ 0) $=\frac{1}{2}, \mathrm{P}(\mathrm{X}=\mathrm{j})=\frac{1}{3^{j}}(\mathrm{j}=1,2,3, \ldots, \infty)$. Then the mean of the distribution and $\mathrm{P}(\mathrm{X}$ is positive and even) respectively are:

If ${\cos ^{ - 1}}\,x\, - \,{\cos ^{ - 1}}\,\frac{y}{2}\, = \,\alpha ,$ where $ - {\kern 1pt} 1\, \le \,x\, \le \,1,\,$ $- {\kern 1pt} 2\, \le \,y\, \le \,2,$ $x\, \le \,\,\frac{y}{2},$ then for all $x, y, 4x^2 -4xy\,\,cos\,\alpha + y^2$ is equal to

$\int\limits^\pi_0\frac{1}{\text{a}+\text{b}\cos\text{x}}\text{ dx}=$

If $\left| {\,\begin{array}{*{20}{c}}a&b&c\\m&n&p\\x&y&z\end{array}\,} \right| = k$, then $\left| {\,\begin{array}{*{20}{c}}{6a}&{2b}&{2c}\\{3m}&n&p\\{3x}&y&z\end{array}\,} \right| = $

For $x \in \left( {0,\frac{3}{2}} \right)$, let $f\left( x \right) = \sqrt x $, $g\left( x \right) = \tan \,x$ and $h\left( x \right) = \frac{{1 - {x^2}}}{{1 + {x^2}}}$. If $\phi \left( x \right) = \left( {\left( {hof} \right)og} \right)\left( x \right)$, then $\phi \left( {\frac{\pi }{3}} \right)$ is equal to

If $\int\frac{\text{x}^3\text{dx}}{\sqrt{1+\text{x}^2}}=\text{a}(1+\text{x}^2)^{\frac{3}{2}}+\text{b}\sqrt{1+\text{x}^2}+\text{c,}$ then :

If $A=\left[\begin{array}{ll}5 & x \\ y & 0\end{array}\right]$ and $A=A^T$, where $A^T$ is the transpose of the matrix $A$, then

Let $\bar r$ be a vector in plane of $\hat i - 2\hat j + \hat k$ and $\hat i - \hat j - \hat k$ such that $\vec r.\left( {\hat i + \hat j} \right) + 2 = 0$ and length of projection of $\vec r$ on $\hat i - \hat j$ is $4\sqrt 2$, then magnitude of vector $\vec r$ is