A resistance wire connected in the left gap of a meter bridge balances a $10\, \Omega$ resistance in the right gap at a point which divides the bridge wire in the ratio $3: 2 .$ If the length of the resistance wire is $1.5 m ,$ then the length of $1\, \Omega$ of the resistance wire is $....... \times 10^{-2}\;m$
NEET 2020, Medium
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$\frac{ R }{10}=\frac{\ell_{1}}{\ell_{2}}$
$\frac{ R }{10}=\frac{3}{2}$
$R=15 \Omega$
Length of $15 \Omega$ resistance wire is $1.5 m$
length of $1 \Omega$ resistance wire $=\frac{1.5}{15}=0.1$
$=1.0 \times 10^{-1} m$
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