Question
A rod of legth l rotates with a uniform angular velocity $\omega$ about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is:
  1. $\text{zero}$
  2. $\frac{1}{2}\text{Bl}\omega^2$
  3. $\text{Bl}\omega ^2$
  4. $2\text{B}\text{l}\omega^2$ 

Answer

  1. $\text{zero}$

Explanation:

Emf at both end is same $=\frac{1}{8}\text{Bwl}^2$

So the potential difference between the two ends of therod is zero.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Assertion :   Base in a transistor is made very thin as compared to collector and emitter regions.                

Reason     : Due to thin base power gain and voltage gain is obtained by a transistor.

(a) If both assertion and reason are true and the reason is the correct explanation of the assertion.

(b) If both assertion and reason are true but reason is not the correct explanation of the assertion.

(c) If assertion is true but reason is false.

(d) If the assertion and reason both are false.

Two sound waves move in the same direction in the same medium. The pressure amplitudes of the waves are equal but the wavelength of the first wave is double the second. Let the average power transmitted across a cross-section by the first wave be P1 and that by the 1 second wave be P2. Then,
  1. P1 = P2
  2. P1 = 4P2
  3. P2 = 2P1
  4. P2 = 4P1

Match List I with List II and select the correct answer using the codes given below the lists :

List I

(Position of the object)

List II

(Magnification)

(I) An object is placed at focus before a convex mirror

(A) Magnification is -

(II) An object is placed at centre of curvature before a concave mirror

(B) Magnification is 0.5

(III) An object is placed at focus before a concave mirror

(C) Magnification is +1

(IV) An object is placed at centre of curvature before a convex mirror

(D) Magnification is  -1

 

(E) Magnification is 0.33

Codes :

(a) I-B, II-D, III-A, IV-E

(b) I-A, II-D, III-C, IV-B

(c) I-C, II-B, III-A, IV-E

(d) I-B, II-E, III-D, IV-C

In a semiconductor:
  1. There are no free electrons at 0K.
  2. There are no free electrons at any temperature.
  3. The number of free electrons increases with temperature.
  4. The number of free electrons is less than that in a conductor.
A rod AB moves with a uniform velocity v in a uniform magnetic field as shown in figure.
  1. The rod becomes electrically charged.
  2. The end A becomes positively charged.
  3. The end B becomes positively charged.
  4. The rod becomes hot because of Joule heating.

Zener breakdown takes place if:

If q is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is

(a)  normal to surface

(b)  normal to surface

(c)   tangential to surface

(d)   tangential to surface

Two point charges Q  and – 3Q are placed at some distance apart. If the electric field at the location of Q is E then at the locality of -3Q, it is

(a) - E

(b) E/3

(c) -3E

(d) -E/3

An equiconvex lens is cut into two halves along (i) XOX¢ and (ii) YOY¢ as shown in the figure.  Let f, f ¢, f ¢¢ be the focal lengths of the complete lens, of each half in case (i), and of each half in case (ii), respectively

Choose the correct statement from the following

 

(a)  

(b)  

(c)

(d)  

A achromatic combination is made with a lens of focal length f and dispersive power ω with a lens having dispersive power of 2ω. The focal length of second will be

(a) 2f

(b) f/2

(c) -f/2

(d) – 2 f