Question
A rod of legth l rotates with a uniform angular velocity $\omega$ about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is:
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$\text{zero}$
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$\frac{1}{2}\text{Bl}\omega^2$
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$\text{Bl}\omega ^2$
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$2\text{B}\text{l}\omega^2$
